But I would almost argue this is a lucky happenstance, not by good program design. What happens if n is 1 or 2? Will this loop return anything, or will it generate a garbage result? In fact, the loop will generate the correct result of 1, which is what F(1) and F(2) are for the Fibonacci sequence.Put one final line of code after the loop terminates, a = a(end) There is no need even for a test on the value of i. Finally, Again, INSIDE the loop, the author has put a test on the number i.my problem is I want them to return as 5 different 3x3 matrices but my code only returns at one matrix 15x3. Algorithm for range estimation Data Items H (K,V): Hash table with loop numbers as keys and list of observed values Procedure processLoopData(LoopID) l. This process gets longer and longer to execute every pass through. I want to do a for loop in matlab for a specific numbers only. Follow 18 views (last 30 days) Show older comments. A for loop that finds multiples of certain numbers in a given range. p 1:N List of all numbers up to N p ( isprime ( p ) ) Remove non-primes. With one step less automation, you could use another in-built isprime. N 10 upper limit p primes (N) List of all primes up to (and including) N. I am trying to create a for loop that finds all values in the range 1,100 that are also multiple of 3 or 5 and save these in a row vector labeled M1. You can use the primes function in MATLAB for this. It would look like this: for index someValue:-1. Learn more about for loop, multiple, mod 3 or 5 MATLAB. In this case you start at the 'end' and move to the beginning. Yet another modfication is traversing backwards. And then it needs to copy over all previous elements each pass through the loop. All you have to do is: for index 2:3:someValue The 3 here tells the loop that it should add 3 to the index at the end of each loop iteration until you get to (or surpass) someValue. In this example, the matrix A has 4 rows and you need to perform a division on each. That in turn means MATLAB needs to reallocate a new vector of length one element longer than the last, at EVERY iteration. Next, define the range of values which the index should loop through. That forces MATLAB to grow the vector in length every pass through the loop. When you will predefine something like this, put it BEFORE the loop starts. Note that you are printing the value of loopcount which is initially 3, but then gets set (and reset) to 7. for i in 1, 2: So your loop iterates twice, since you have 2 print statements in the loop your get 4 lines of output. So every iteration of the loop redefines a(2), as 1. In your case: loopcount 3 for i in range (1, loopcount): becomes.
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